I want to count how many If/Else statements I have in my function.

My code looks like this:

def countdown(type):
    if type==1:
       //code
    elif type==2:
      //code
    else:
        print(f"You have reached the end of the script."
              f"The maximum type of countdowns are: {x}")
        exit(1)

wherex, should have the number of if queries (If/Else).In this case, there are 3 queries.If I create another if/else query in this function, I don't have to change the warning at the bottom of the script.

Is this even possible?

I am using Python 3.10

uj5u.com enthusiastic netizens replied:

Do not useif..else , use a dictionary or list instead:

types={
    1:...,
    2:...
}

try:
    types[type]
except KeyError:
    print(f"You have reached the end of the script."
          f"The maximum type of countdowns are: {len(types)}")
    exit(1)

Exactly what to put into the dict as values ​​depends...can you generalize this calculus method, so you just need to put a value into the dict instead of the actual code? Great.Otherwise, put the function in a dictionary:

types={1: lambda:..., 2: some_func, 3 : self.some_method}

...

types[type]()

uj5u.com enthusiastic netizens replied:

Since you are using Python 3.10, you can use new match operator.An example:

def countdown(type):
    match type:
        case 1:
            # code
        case 2:
            # code
        case _:
            print(f"You have reached the end of the script."
                  f"The maximum type of countdowns are: {x}")
            exit(1)

For me this is a more readable solution than a font>dict.

How to count the number of options, let's consider we have nDifferent and logically separated options.In this case, I recommend you enum:

from enum import IntEnum
class CountdownOption(IntEnum):
    FIRST=1
    SECOND=2
    #...

#...

def countdown(type):
    match type:
        case CountdownOption.FIRST:
            # code
        case CountdownOption.SECOND:
            # code
        case _:
            print(f"You have reached the end of the script."
                  f"The maximum type of countdowns are: {len(CountdownOption)}")
            exit(1)